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In a previous article, Creating a WYSIWYG font ComboBox using C#, there is a hacky bit of code which uses a try catch block to handle processing when a given font style doesn't exist. This article describes a better way of handling this requirement without relying on the exception handler.

Originally we used the following code to determine if a font style exists: (Some of the additional code has been removed for clarity)

// bad code do not use!

protected virtual Font GetFont(string fontFamilyName)
{
  Font font;

  font = this.GetFont(fontFamilyName, FontStyle.Regular);
  if (font == null)
    font = this.GetFont(fontFamilyName, FontStyle.Bold);
  if (font == null)
    font = this.GetFont(fontFamilyName, FontStyle.Italic);
  if (font == null)
    font = this.GetFont(fontFamilyName, FontStyle.Bold | FontStyle.Italic);

  return font;
}

protected virtual Font GetFont(string fontFamilyName, FontStyle fontStyle)
{
  Font font;

  try
  {
    font = new Font(fontFamilyName, this.PreviewFontSize, fontStyle);
  }
  catch
  {
    font = null;
  }

  return font;
}

This code essentially "tests" each style by attempting to create a font instance of a given style. If the style doesn't exist, an exception is thrown and the code moves onto the next style.

A better way is to use the IsStyleAvailable function of the FontFamily object. You simply create an instance of this object with the name of the font you wish to query, then call the method with the style to test. Note that the constructor for FontFamily will throw an exception if the font you try to create doesn't exist.

Switching the GetFont method above to use IsStyleAvailable ends up looking like this:

protected virtual Font GetFont(string fontFamilyName)
{
  Font font;

  using (FontFamily family = new FontFamily(fontFamilyName))
  {
    if (family.IsStyleAvailable(FontStyle.Regular))
      font = this.GetFont(fontFamilyName, FontStyle.Regular);
    else if (family.IsStyleAvailable(FontStyle.Bold))
      font = this.GetFont(fontFamilyName, FontStyle.Bold);
    else if (family.IsStyleAvailable(FontStyle.Italic))
      font = this.GetFont(fontFamilyName, FontStyle.Italic);
    else if (family.IsStyleAvailable(FontStyle.Bold | FontStyle.Italic))
      font = this.GetFont(fontFamilyName, FontStyle.Bold | FontStyle.Italic);
    else
      font = null;
  }

  return font;
}

protected virtual Font GetFont(string fontFamilyName, FontStyle fontStyle)
{
  return new Font(fontFamilyName, this.PreviewFontSize, fontStyle);
}

Based on this, a simple method to check if a given font name and style exists is presented below. As the constructor for FontFamily throws an ArgumentException if the given font doesn't exist, we can trap that and return false. Any other error will be thrown, rather than being silently ignored as in our earlier solution.

public bool DoesFontExist(string fontFamilyName, FontStyle fontStyle)
{
  bool result;

  try
  {
    using (FontFamily family = new FontFamily(fontFamilyName))
      result = family.IsStyleAvailable(fontStyle);
  }
  catch (ArgumentException)
  {
    result = false;
  }

  return result;
}

• 2011-08-07 - First published
• 2020-11-21 - Updated formatting

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Comments

Jason

# 29 April 2013 Reply

Okay... so is the following "wrong"?...

///

/// Performs a case-insensitive lookup against the installed Window's fonts ///

/// /// public static bool IsFontInstalled(string fontName) { if (string.IsNullOrWhiteSpace(fontName)) return false;

        bool isFontInstalled = false;

        using (InstalledFontCollection installedFontCollection = new InstalledFontCollection())
        {
            foreach (FontFamily fontFamily in installedFontCollection.Families)
            {
                if (0 == string.Compare(fontFamily.Name, fontName, ignoreCase: true))
                {
                    isFontInstalled = true;
                    break;
                }
            }
        }

        return isFontInstalled;
    }
}

Richard Moss

# 30 April 2013 Reply

Hello,

No, there's nothing wrong with your approach. The only real difference is you are just checking that any style in a given font exists whereas I am checking that a specific style exists. But either way, your code is fine.

Regards; Richard Moss

yetaland

# 26 November 2013 Reply

thank you !

Franc

# 24 December 2015 Reply

Thanks.